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Electronic circuits and components * Course Index * Introduction * About the Author * About this Course * Feedback * Course Navigation * How to use this Course * TINA * Locktronics Fundamentals * Introduction: Fundamentals * Units and Multiples * Electricity * Electronic Principles * Electrical Circuits ## Basic Lamp Circuit ## Lamps in Series ## Lamps in Parallel * Alternating Current * Assessment: Fundamentals Passive Components * Introduction: Passive Components * Resistors * Capacitors * Inductors * Transformers * Batteries, Fuses, Lamps and Switches * Assessment: Passive Components Semiconductors * Introduction: Semiconductors * Diodes * Transistors * Logic Gates * Assessment: Semiconductors Passive Circuits * Introduction: Passive Circuits * Series and Parallel Connections * Kirchoff's Laws * Potential and Current Dividers * Passive Time Variant Circuits * Assessment: Passive Circuits Active Circuits * Introduction: Active Circuits * Power Supply Circuits * Operational Amplifier Circuits * Transistor Amplifier Circuits * 555 Timer Circuits * Assessment: Active Circuits Parts Gallery * Introduction: Parts Gallery * Passive Component Images * Semiconductor Images * Other Images * Quizzes |
(:Summary:Contains the 'action' links (like Browse, Edit, History, etc.), placed at the top of the page, see site page actions:) (:comment This page can be somewhat complex to figure out the first time you see it. Its contents are documented at PmWiki.SitePageActions if you need help. :) * Print (:comment (:if group Site,SiteAdmin,Cookbook,Profiles,PmWiki*:) (:comment delete if and ifend to enable backlinks:) * %item rel=nofollow class=backlinks accesskey='$[ak_backlinks]'% [[{*$Name}?action=search&q=link={*$FullName} | $[Backlinks] ]] (:ifend:) :) * Login Lamps in Series<^< Basic Lamp Circuit | Course Index | Lamps in Parallel >^>(:nl:) ![]() In the series connected circuit, two 3V 3W lamps are connected in series in order to consume a total power of 6W from the 6V supply. Once again, the current flowing in each lamp can be calculated from: I = P/V = 3W/3V = 1A Note that the same current (i.e. 1A) flows in each lamp. Applying Ohm's Law to determine the working resistance of each lamp (i.e. the resistance when illuminated) gives: R = V/I = 3V/1A = 3Ω The effective resistance of the circuit must be 6Ω (i.e. 3Ω + 3Ω). (:nl:)(:table style="clear:both":)
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