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<^< Current flow Model | Course index | Transistor as a Current Amplifier >^>

Electronic circuits and components * Course Index * Introduction * About the Author * About this Course * Feedback * Course Navigation * How to use this Course * TINA * Locktronics

Fundamentals * Introduction: Fundamentals * Units and Multiples * Electricity * Electronic Principles * Electrical Circuits * Alternating Current * Assessment: Fundamentals

Passive Components * Introduction: Passive Components * Resistors * Capacitors * Inductors * Transformers * Batteries, Fuses, Lamps and Switches * Assessment: Passive Components

Semiconductors * Introduction: Semiconductors * Diodes * Transistors ## Transistor Construction ## Transistor Symbols and Connections ## Transistor Operation ## Current flow Model ##

Examples: Current Flow Model ## Transistor as a Current Amplifier ## Worksheet: Transistor as a Current Amplifier ## Transistor as a Switch * Logic Gates * Assessment: Semiconductors

Passive Circuits * Introduction: Passive Circuits * Series and Parallel Connections * Kirchoff's Laws * Potential and Current Dividers * Passive Time Variant Circuits * Assessment: Passive Circuits

Active Circuits * Introduction: Active Circuits * Power Supply Circuits * Operational Amplifier Circuits * Transistor Amplifier Circuits * 555 Timer Circuits * Assessment: Active Circuits

Parts Gallery * Introduction: Parts Gallery * Passive Component Images * Semiconductor Images * Other Images * Quizzes

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Examples Current Flow Model

<^< Current flow Model | Course Index | Transistor as a Current Amplifier >^>(:nl:)

>>frame round<< Example 1:

A transistor operates with a collector current of 18 mA and a base current of 0.5 mA.

Determine the value of emitter current. >><<

>>id=example1 class=question margin=10px frame round<< In this case, I'_C_' = 18 mA and I'_B_' = 0.5 mA.

Now I'_E_' = I'_B_' + I'_C_' thus I'_E_' = (18 + 0.5) = 18.5 mA. >><<

>>frame round<< Example 2:

A transistor operates with a collector current of 2.5 mA.

If the emitter current is 2.58 mA determine the base current. >><<

>>id=example2 class=question margin=10px frame round<< In this case, I'_C_' = 2.5 mA and I'_E_' = 2.58 mA.

Now I'_E_' = I'_B_' + I'_C_' thus I'_B_' = I'_E_' - I'_C_' from which I'_B_' = (2.58 - 2.5) = 0.08 mA. >><< (:nl:)(:table style="clear:both":)

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