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<^< Magnetic Field Strength | Course index | Electrical Circuits >^>

Electronic circuits and components * Course Index * Introduction * About the Author * About this Course * Feedback * Course Navigation * How to use this Course * TINA * Locktronics

Fundamentals * Introduction: Fundamentals * Units and Multiples * Electricity * Electronic Principles ## Electrostatics ## Electric Fields ## Capacitance ## Charge on a Capacitor ## Electric Field Strength ## Examples: Electric Field Strength ## The Unit of Capacitance ## Charge Capacitance and Voltage ## Energy Stored in a Capacitor ## Examples: Capacitance ## The Unit of Inductance ## Flux Linkage and Current ## Energy Stored in an Inductor ## Examples: Inductance ## Magnetism ## Electromagnetism ## Magnetic Fields ## Electromagnets ## Magnetic Field Strength ##

Examples: Magnetism * Electrical Circuits * Alternating Current * Assessment: Fundamentals

Passive Components * Introduction: Passive Components * Resistors * Capacitors * Inductors * Transformers * Batteries, Fuses, Lamps and Switches * Assessment: Passive Components

Semiconductors * Introduction: Semiconductors * Diodes * Transistors * Logic Gates * Assessment: Semiconductors

Passive Circuits * Introduction: Passive Circuits * Series and Parallel Connections * Kirchoff's Laws * Potential and Current Dividers * Passive Time Variant Circuits * Assessment: Passive Circuits

Active Circuits * Introduction: Active Circuits * Power Supply Circuits * Operational Amplifier Circuits * Transistor Amplifier Circuits * 555 Timer Circuits * Assessment: Active Circuits

Parts Gallery * Introduction: Parts Gallery * Passive Component Images * Semiconductor Images * Other Images * Quizzes

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Examples: Magnetism

<^< Magnetic Field Strength | Course Index | Electrical Circuits >^>(:nl:)

>>frame round<< Example 1:

A flux density of 2.5mT is developed in free space over an area of 20cm'^2^'.

Determine the total flux present. >><<

>>id=example1 class=question margin=10px frame round<< Re-arranging the formula B = &#934;/A to make &#934; the subject gives:

&#934; = B A thus &#934; = 2.5 x 10'^-3^' x 20 x 10'^-4^' = 0.5 x 10'^-6^' Wb >><<

>>frame round<< Example 2:

A solenoid comprises 1,000 turns of wire. If the mean length of the magnetic circuit is 0.05m determine the current that must be supplied to the solenoid in order to produce a magnetic field intensity of 200 A/m. >><<

>>id=example2 class=question margin=10px frame round<< Since H = N x I / L , I = H x L / N

Thus I = 200 x 0.05/1,000 = 10/1,000 = 10mA >><<(:nl:)(:table style="clear:both":)

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Page last modified on August 15, 2011, at 02:07 PM